Air standards cycles
For a Carnot engine operating between two thermal reservoirs at temperatures \( T_H = 600 \text{K} \) and \( T_C = 300 \text{K} \), what is the maximum possible efficiency?
- 0.25
- 0.5
- 0.75
- 1.0
Explanation:
- The maximum possible efficiency for any heat engine is given by the Carnot efficiency: \( \eta = 1 – \frac{T_C}{T_H} \), where temperatures are in Kelvin.
- Substituting the values: \( \eta = 1 – \frac{300}{600} = 1 – 0.5 = 0.5 \) or 50%.
- 1.0 (or 100%) represents an ideal, impossible perpetual motion machine of the second kind, violating the Second Law of Thermodynamics.
